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7b^2-52b+60=0
a = 7; b = -52; c = +60;
Δ = b2-4ac
Δ = -522-4·7·60
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-32}{2*7}=\frac{20}{14} =1+3/7 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+32}{2*7}=\frac{84}{14} =6 $
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